Exam with Answer Key Template
Exam paper with point allocation, multiple choice, short answer and problems, KaTeX worked solutions and marking guidance
使用方法: Use to set a written exam and its marking scheme together. Build the point allocation from learning outcomes first, then write each solution with marks per step. Main pitfall: printing the student version without removing the answer key section.
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Exam: [Course code] [Exam name] with Answer Key
Exam paper template with a separate answer key: candidate instructions, multiple-choice, short-answer and extended problem sections, a point allocation table, worked solutions written in KaTeX math, and marking guidance. The sample questions use introductory calculus and algebra so the format is concrete; replace them with your own. Based on common assessment practice.
| Field | Value |
|---|---|
| Course | [MATH 110 Calculus I] |
| Exam | [Midterm exam 1] |
| Date / time | YYYY-MM-DD, [09:00-10:30] |
| Duration | [90 minutes] |
| Total points | [50] |
| Permitted materials | [Non-programmable calculator; one A4 formula sheet] |
| Examiner | [@name] |
| Moderator | [@name] |
| Version | [A] |
1. Instructions to candidates
- Write your name and student ID on every page.
- Answer all questions in Sections A, B and C.
- In Section A, circle one answer per question. No working is required.
- In Sections B and C, show all working. Correct answers without working may receive limited credit.
- Give exact answers unless a question asks for a decimal approximation.
- If you believe a question contains an error, state your assumption and answer the question as you interpret it.
- Points for each question are shown in brackets.
| Name | Student ID | Seat |
|---|---|---|
| [ ] | [ ] | [ ] |
2. Point allocation
| Section | Questions | Points each | Section total | Learning outcomes |
|---|---|---|---|---|
| A. Multiple choice | 1-5 | 2 | 10 | LO1, LO2 |
| B. Short answer | 6-8 | 4 | 12 | LO2, LO3 |
| C. Problems | 9-10 | 14 | 28 | LO2, LO3, LO4 |
| Total | 10 | 50 |
Check: 10 + 12 + 28 = 50.
3. Section A: Multiple choice (10 points)
Q1. [2] What is ?
(a) (b) (c) (d)
Q2. [2] Evaluate .
(a) 3 (b) 6 (c) 9 (d) 18
Q3. [2] What is ?
(a) 0 (b) 1 (c) (d) The limit does not exist
Q4. [2] What is ?
(a) (b) (c) (d)
Q5. [2] What is the slope of the tangent to at ?
(a) 3 (b) 6 (c) 9 (d) 2
4. Section B: Short answer (12 points)
Q6. [4] Use the product rule to differentiate .
Q7. [4] Find the critical points of and classify each as a local maximum or local minimum.
Q8. [4] Solve .
5. Section C: Problems (28 points)
Q9. [14] Let .
(a) [6] Find .
(b) [3] Evaluate .
(c) [5] Find the equation of the tangent line to at .
Q10. [14]
(a) [8] Find the area of the region enclosed by and .
(b) [6] Solve the system of equations
6. Answer key
6.1 Section A
| Question | Answer | Common wrong answer and the error it reveals |
|---|---|---|
| Q1 | (b) | (d): integrated instead of differentiated |
| Q2 | (c) 9 | (d): forgot to divide by 2 when integrating |
| Q3 | (b) 1 | (d): treated as undefined without taking the limit |
| Q4 | (c) | (a): omitted the chain rule factor |
| Q5 | (b) 6 | (c): gave the -value instead of the slope |
Worked note for Q2:
6.2 Section B
Q6. Product rule with , :
Marks: rule stated or applied correctly [2]; each term correct [1 + 1].
Q7. Differentiate and set to zero:
Second derivative . At , : local minimum, . At , : local maximum, .
Marks: [1]; both critical points [1]; correct classification of each with justification [1 + 1]. Accept a sign chart of instead of .
Q8. Divide by 2 and factor:
Marks: simplification or correct use of the quadratic formula [2]; each root [1 + 1]. Check: and .
6.3 Section C
Q9 (a). Chain rule with outer function and inner :
Marks: derivative of outer function [2]; derivative of inner function [2]; correct product and simplification [2].
Q9 (b).
Marks: substitution [1]; arithmetic [2]. Follow-through: award full marks for correct evaluation of an incorrect from part (a).
Q9 (c). and , so the tangent line is
Marks: point [1]; slope [2]; line equation [2].
Q10 (a). Intersections: . On , , so
Marks: limits of integration [2]; correct integrand with the upper curve first [1]; antiderivative [3]; final value [2]. Accept .
Q10 (b). Adding the equations eliminates :
Marks: valid elimination or substitution [3]; [1]; [1]; check in both equations [1].
7. Marking guidance
- Award method marks for correct reasoning even when an arithmetic slip leads to a wrong final answer.
- Apply follow-through: an error in one part is penalised once, and later parts are marked on the student's own earlier value.
- Accept any correct equivalent form (for example or ).
- Do not award marks for a correct answer obtained by clearly invalid working.
- Use half-marks only where the scheme shows them.
- Second-mark a sample of [10%] of scripts, including all scripts within [2] points of a grade boundary.
| Date | Question | Unexpected answer | Decision |
|---|---|---|---|
| Example: YYYY-MM-DD | Q7 | Classified points using a graph sketch only | 1 of 2 classification marks: justification incomplete |
| [Date] | [Question] | [Answer] | [Decision] |
Results summary
| Statistic | Value |
|---|---|
| Scripts marked | [n] |
| Mean (SD) | [ ] |
| Questions with mean below 50% | [ ] |
| Action for next exam or teaching | [ ] |
Standard and licence note
Based on common assessment practice for written examinations and marking schemes. Original text written for this collection; sample questions and solutions are illustrative and were checked for correctness. Template licence: MIT.
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